Structural Dynamics / Impulse response, arbitrary loading and convolution
Pulses, and why duration is everything
Step, ramp, rectangular, triangular and half-sine — and the single ratio that decides which of them you need to care about.
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Read the lesson register and outstanding review notesWhy this matters
For an undamped linear oscillator, a suddenly applied sustained load reaches twice its static displacement. A finite pulse gives a different peak depending on its shape and duration. The rectangular-pulse shock spectrum starts at zero as duration tends to zero at fixed peak force, reaches 2 at half a natural period and stays at 2 for longer durations. Other pulse shapes have different curves.
By the end of this lesson you should be able to
- Compute the response to the standard idealised pulses
- Explain the two branches of a shock spectrum and what divides them
- Say why the peak response can occur after the load has gone
- Show that pulse SHAPE stops mattering once the pulse is short enough
Compare the load timescales
The ratio td/Tn compares pulse duration with the natural period, but duration alone does not define the response. Rise time, fall time, shape and damping also matter.
An impulse approximation is useful when the structure moves little during the pulse: td/Tn must be much smaller than 1, with the approximation checked for the response being used. Equal-area pulses then give approximately equal global responses. They need not give equal local stresses, contact forces or nonlinear damage.
A quasi-static approximation requires sufficiently slow changes throughout the load history. An abrupt start can create a large transient even when the load remains on for many periods.
Rectangular-pulse shock spectrum
For an undamped SDOF system initially at rest, a rectangular pulse of peak F0 gives:
| Duration ratio | Peak displacement divided by F0/k |
|---|---|
| td/Tn < 0.5 | 2 sin(π td/Tn) |
| td/Tn ≥ 0.5 | 2 |
The peak after a short rectangular pulse occurs during free vibration. At half a period or longer, the response reaches the sustained-step peak while the load is still acting. The factor 0.5 separates these exact rectangular-pulse branches; it is not a general boundary for impulse accuracy.
For example, the ideal impulse approximation overestimates the short rectangular-pulse peak by about 1.7% at td/Tn=0.1 and about 11% at 0.25. Choose the approximation according to the required accuracy, and compute the finite history when necessary.
What it calculates: Peak response as a multiple of the static deflection under the peak force
- td
- Pulse duration (s)
- Tn
- Natural period of the structure (s)
- DLF
- Dynamic load factor, xmax/(F₀/k) (—)
This assumes
- Rectangular pulse of constant magnitude F₀
- No damping — this is the upper bound
- Linear elastic single-degree-of-freedom response
In plain terms: The factor never exceeds 2, whatever the pulse duration. A rectangular pulse cannot do worse than a step, because a step is what it becomes when it lasts long enough. Short pulses do progressively less, and the transition is at exactly half a natural period.
Try it
Build a force history and see what it does
Choose a shape and change how long it lasts, measured against the structure's own natural period.
Pulse shape
The single most important parameter on this panel.
- Response
- Static deflection F₀/k
Show the numbers behind this plot
- Static displacement
- 36.5 mm
- Peak displacement
- 57.4 mm
- Dynamic load factor
- 1.57
- Peak occurs at
- 0.24 s
- Total impulse ∫F dt
- 10.9 kN·s
- Impulsive estimate I/(mω)
- 69.1 mm
- Rectangular shock spectrum
- 1.62
after the pulse has ended — the structure is in free vibration
Not applicable — this pulse is not short compared with Tn
Around td ≈ Tn/2 the pulse and the structure are in step, and this is where the dynamic load factor is largest. It is 1.57 here.
What this shows: What decides the response to a pulse is not its magnitude or even its shape, but its DURATION measured against the natural period. Below about half a period only the area under the curve matters.
Worked example
A blast-resistant panel, checked three ways
Given
- A façade panel spanning 3.5 m, idealised as SDOF
- Natural frequency 14 Hz
- A pressure pulse falling linearly from 45 kPa at t=0 to zero at 18 ms
- Panel area 3.5 × 1.2 m; damping neglected, which is conservative
Find
The peak response, treated as static, as impulsive, and properly.
Assumptions
- The panel stays elastic — a real blast design would not assume this, and the point here is the comparison of methods
- Damping neglected: over a fraction of one cycle it removes almost nothing
Predict first
A rectangular pulse and a triangular pulse have the same peak force and the same duration, which is very short compared with the natural period. Which produces the larger response?
Practice
A rectangular pulse lasts 0.06 s on a structure with a natural period of 0.4 s. Using the undamped shock spectrum, what is the dynamic load factor?
Practice
For the same structure, what pulse duration in seconds would give the maximum dynamic load factor of 2?
Practice
A triangular pulse has a peak of 80 kN and lasts 0.025 s. What is its impulse, in kN·s?
Check yourself
For a pulse with td/Tn = 0.2, when does the peak response occur?
Worked example
The same impulse, delivered three ways
Given
- A structure with a natural period of 0.5 s
- A rectangular pulse of the same total impulse, delivered over 0.05 s, 0.25 s and 2.0 s
Find
How the peak response differs
Summary
- td/Tn is the single ratio that decides the treatment
- Use td/Tn≪1 for an impulse approximation, and slow rise/fall times for quasi-static response; check accuracy against the actual history
- Rectangular shock spectrum: DLF = 2 sin(π td/Tn) below 0.5, and 2 above it
- In the short-pulse limit, impulse controls the leading-order global response
- The impulsive DLF can be written neatly as Iωn/F₀
- For a short pulse the peak occurs AFTER the load has gone
- 'DLF = 2 to be safe' is neither safe nor conservative outside the step-load case