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Learning / bridge engineering

cable

Inclined cable equilibrium

Lesson review: expert verification remains open

This lesson has received a full-context editorial review and a check of its technical explanations. Selected arithmetic has been checked separately. This is not independent engineering sign-off.

Checks needed for project use

  • Bridge component studies and adjustable examples still need an independent bridge-engineering review, including applicability, load models and detailing guidance.
  • Specialist review remains for: Use tension-only elements and nonlinear geometry; establish the equilibrium shape and construction-stage cable forces. The diagonal calculation is a local idealisation; it does not verify the displayed bridge or applicable design requirements.

These are educational models and exercises. Check their assumptions before using the results. The full technical content and every diagram have not yet been independently verified.

Concrete and steel calculations retain their stated first-generation Eurocode teaching basis. Use the standards and amendments specified for your project; do not mix generations without an appropriate design basis.

Read the lesson register and outstanding review notes

Loads and actions

Cables carry tension. Their geometry and initial force control stiffness and load redistribution.

Choose a model

Use tension-only elements and nonlinear geometry; establish the equilibrium shape and construction-stage cable forces.

Design considerations

Check cable and anchorage resistance, fatigue, vibration, corrosion protection and replacement. Towers and deck must resist horizontal components.

Durability and maintenance

Inspect anchorages, sheathing, dampers and signs of water entry; plan how forces transfer during replacement.

Inclined cable equilibrium

A single local free-body diagram. Global load sharing, prestress, asymmetry and construction sequence are omitted.

Local equilibrium for the stated member geometry and loading; no member sizing or stability check.

N = P/sin45° = 282.8 kN; horizontal component = 200.0 kN